Of course, this is true for every segment i, so we can add up all of these to find the
work done across the entire displacement, from x
1
to x:
(((
1
2
2
2
1
2
1
2
1
2
3
2
1
2
2
2
1
2
4
2
1
2
3
2
1
mvmvmvmvmvmv
FxF
---)+)+)+...=
+∆
223
∆∆xFx++...
By looking closely at the left-hand side, you can see that most of the terms will cancel!
We are left with just two terms:
1
2
2
1
2
1
2
mvmv
n
-
So we can rewrite this equation as:
1
2
2
1
2
1
2
1
mvmvFx
ni
i
n
-=
=
∑
∆
We have added up the little pieces of work done at each instant to get the total change
in energy—the work W. You’ll see that this looks awfully similar to the definition of an inte-
gral. It ...
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