Name
[2.0]
year-from-dateTime()
Given an xs:dateTime
value, returns its year
value.
Syntax
xs:integer?year-from-dateTime(
xs:dateTime?
)
Inputs
An xs:dateTime
value.
Output
An xs:integer
representing the year component of the given xs:dateTime
value. If the argument is
the empty sequence, this function returns the empty
sequence.
Defined in
XQuery 1.0 and XPath 2.0 Functions and Operators section 10.5, “Component Extraction Functions on Durations, Dates and Times.”
Example
This stylesheet demonstrates the year-from-dateTime()
function:
<?xml version="1.0"?> <!-- year-from-datetime.xsl --> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:output method="text"/> <xsl:template match="/"> <xsl:text>
Extracting the year from an xs:dateTime:</xsl:text> <xsl:variable name="currentDateTime" as="xs:dateTime" select="current-dateTime()"/> <xsl:text>

The current date and time is: </xsl:text> <xsl:value-of select="$currentDateTime"/> <xsl:text>

 The current year: </xsl:text> <xsl:value-of select="year-from-dateTime($currentDateTime)"/> <xsl:text>
 In words: </xsl:text> <xsl:value-of select="format-dateTime($currentDateTime, '[YWw]')"/> <xsl:text>
 In German: </xsl:text> <xsl:value-of select="format-dateTime($currentDateTime, '[YWw]', 'de', (), ())"/> </xsl:template> </xsl:stylesheet>
The stylesheet creates these results:
The current date and time is: 2006-11-16T05:18:20.187-05:00 The current year: ...
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