
218 Iterative Optimization in Inverse Problems
15.4.2 The General Case
Now we have x
k+1
= Tx
k
where S = γG and T = P
C
(I −SP
C
(I −S)).
We assume that Tz = z,sothatz solves VIP(G, C).
The key Proposition now is the following.
Proposition 15.1 Let G : C → R
J
be pseudo-monotone and L-Lipschitz,
let σ = γL < 1,andletS = γG. For any k let y
k
= P
C
(I −S)x
k
.Then
z − x
k
2
−z − x
k+1
2
≥ (1 −σ
2
)y
k
− x
k
2
. (15.13)
The proof of Proposition 15.1 follows that in [120]. The inequality in
(15.13) emerges as a consequence of a sequence of inequalities and equa-
tions. We list these results first, and then discuss their proofs. For conve-
nience, we let w
k
= x
k
− Sx
k
.
1. Sy
k
,y
k