May 2024
Intermediate to advanced
872 pages
32h 3m
English
Solved ProblemS
Problem 1
CH3COOH (50 ml, 0.1 M) is titrated against 0.1 M NaOH solution. Calculate the pH at the addition of 0 ml, 10 ml, 20 ml, 25 ml, 40 ml, 50 ml and 60 ml of
of CH3COOH is 2 × 10–5.
Solution
(i) When 0 ml of NaOH is added, the pH is due to acetic acid,
∴ [H+] =
=
= ![]()
pH = –log
= – [log 2–6] = 3–0.15 = 2.85
(ii) When 10 ml ...
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