Learning JavaScript

Chapter 3

1. The solution is:

2. var resultOfComp = (valA - valB) % 3 / 2 * (4 + valC) - 3;

3. The solution is:

4. switch(val) {
      case 'one','two' : 
        result = 'OK';
        break;
      case 'three' :
        result = 'OK2';
        break;
      default :
        result = 'NONE';
   }

5. The solution is:

6. if ((varOne == 33) && (varTwo <= 100) && (varThree > 0))...

7. and 5. In for loops, you don’t have to start at 0 or 1, and you also don’t have to increment the number. Here’s how to count upward between 10 and 20:

8. for (var i = 11; i < 20; i++) {
     document.writeln(i + "<br />");
   }

9. And here’s how to reverse the count:

10. for (var i = 19; i > 10; i--) {
      document.writeln(i + "<br />");
    }