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Perl Cookbook
book

Perl Cookbook

by Tom Christiansen, Nathan Torkington
August 1998
Intermediate to advanced
800 pages
39h 20m
English
O'Reilly Media, Inc.
Content preview from Perl Cookbook

Expanding Variables in User Input

Problem

You’ve read in a string with an embedded variable reference, such as:

You owe $debt to me.

Now you want to replace $debt in the string with its value.

Solution

Use a substitution with symbolic references if the variables are all globals:

$text =~ s/\$(\w+)/${$1}/g;

But use a double /ee if they might be lexical (my) variables:

$text =~ s/(\$\w+)/$1/gee;

Discussion

The first technique is basically “find what looks like a variable name, and then use symbolic dereferencing to interpolate its contents.” If $1 contains the string somevar, then ${$1} will be whatever $somevar contains. This won’t work if the use strict 'refs' pragma is in effect because that bans symbolic dereferencing.

Here’s an example:

use vars qw($rows $cols);
no strict 'refs';                   # for ${$1}/g below
my $text;

($rows, $cols) = (24, 80);
$text = q(I am $rows high and $cols long);  # like single quotes!
$text =~ s/\$(\w+)/${$1}/g;
print $text;

                  I am 24 high and 80 long

You may have seen the /e substitution modifier used to evaluate the replacement as code rather than as a string. It’s designed for situations such as doubling every whole number in a string:

$text = "I am 17 years old";
$text =~ s/(\d+)/2 * $1/eg;

When Perl is compiling your program and sees a /e on a substitute, it compiles the code in the replacement block along with the rest of your program, long before the substitution actually happens. When a substitution is made, $1 is replaced with the string that matched. The code to ...

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Publisher Resources

ISBN: 1565922433Catalog PageErrata