
89Air Injection in Chutes
© 2010 Taylor & Francis Group, LLC
For the forward ow, Equation 3.40 will appear as:
P
dx
v
k
m
=− +
λρψβ ρ
2
21
1212
2
*
; (3.53)
for the reverse ow:
P
v
D
k
vv
dx
m
=− +
λρψβ ρ
2
21
12
2
*
()
. (3.54)
By integrating Equations 3.53 and 3.54 along the tube length, we obtain, respectively:
x
D
v
k
dx
m
−=−+
∫
0
2
21
1212
2
λρψβ ρ
*
, (3.55)
x
D
v
k
vv
m
−=−+
∫
0
2
21
12
2
λρψβ ρ
*
. (3.56)
For the rst part, the integral represents the air pressure drop at a tube section of
x length that results from the fall of material. We refer to this pressure drop value
as the induction pressure [49, 70]. If there is no directional ai ...