March 2013
Intermediate to advanced
172 pages
4h 22m
English
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Chapter 6
1. Schlaifer (1969).
2. Keeney & Raiffa (1976).
3. Abbas (2010). pp. 62–98.
4. Keeney (1977). pp. 267–310; Kirkwood (1992). pp. 28–39.
5. Keeney & Raiffa (1976).
6. Keeney & Raiffa (1976).
7. Kirkwood (1997).
8. Clemen (1996).
9. Keeney & Raiffa (1976).
10. von Winterfeldt & Edwards (1986).
11. With a specified mid-value of $50 million, the normalized mid-value is ($50M–$0M)/($250M–$0M) = 50/250 = 0.20. For a normalized mid-value of 0.20, Figure 3.6 shows that the normalized exponential constant is 0.305. Therefore, the exponential constant is 0.305 * ($250M–$0M) = $76.25 million (approx. $75 million).
12. With a specified mid-value of $10 million, the normalized mid-value is ($50M–$10M)/($50M–$0M) = 40/50 = 0.80. For a normalized ...
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