Conversion Operators
C#
will
convert int
to
long
implicitly, and allow you to convert
long
to int
explicitly. The
conversion from int
to long
is
implicit
because you know that any
int
will fit into the memory representation of a
long
. The reverse operation, from
long
to int
, must be
explicit
(using a cast) because it is
possible to lose information in the conversion:
int myInt = 5; long myLong; myLong = myInt; // implicit myInt = (int) myLong; // explicit
You want the same functionality for your fractions. Given an
int
, you can support an implicit conversion to a
fraction because any whole value is equal to that value over 1 (e.g.,
15==15/1
).
Given a fraction, you might want to provide an explicit conversion
back to an integer, understanding that some value might be lost.
Thus, you might convert 9/4
to the integer value
2
.
The keyword implicit
is used
when the conversion is guaranteed to succeed and no information will
be lost; otherwise explicit
is used.
Example 6-1 illustrates how you might implement
implicit and explicit conversions, and some of the operators of the
Fraction
class. (Although I’ve used
Console.WriteLine
to print messages illustrating which
method we’re entering, the better way to pursue this kind of
trace is with the debugger. You can place a breakpoint on each of the
test statements, and then step into the code, watching the invocation
of the constructors as they occur.)
Example 6-1. Defining conversions and operators for the fraction class operators ...
Get Programming C# now with the O’Reilly learning platform.
O’Reilly members experience books, live events, courses curated by job role, and more from O’Reilly and nearly 200 top publishers.