
Chapter 2
How Inductance and Inductor Size Depend on Frequency
The following discussion applies to all the topologies.
If keeping everything else fixed (including D) we double the frequency, the voltseconds will
halve, because the durations t
ON
and t
OFF
have halved. But since ∆I is “voltseconds per unit
inductance,” this too will halve. Further, since I
DC
has not changed, r = ∆I/I
DC
will also
halve. So if we started off with r = 0.4, we now have r = 0.2.
If we want to return the converter to the optimum value of r = 0.4, we will now need to
somehow double the ∆I we were left with at the end of the last step. The way to do that is to
halve the inductance