)를 제곱한 후, 그 총합을 구합니다. 그러면 이 평균 제곱 오차를 파이썬으로 구현해봅시다.
def mean
_
squared
_
error
(
y
,
t
):
return 0
.
5
*
np
.
sum
((
y
-
t
)**
2
)
여기에서 인수
y
와
t
는 넘파이 배열입니다. 이 코드는 [식
4
.
1
]을 그대로 구현한 것이니 설명은
생략합니다. 그러면 이 함수를 실제로 사용해보죠.
>>>
# 정답은 '2'
>>>
t
=
[
0
,
0
,
1
,
0
,
0
,
0
,
0
,
0
,
0
,
0
]
>>>
>>>
# 예
1
:
'
2
'
일 확률이 가장 높다고 추정함
(
0
.
6
)
>>>
y
=
[
0
.
1
,
0
.
05
,
0
.
6
,
0
.
0
,
0
.
05
,
0
.
1
,
0
.
0
,
0
.
1
,
0
.
0
,
0
.
0
]
>>>
mean
_
squared
_
error
(
np
.
array
(
y
),
np
.
array
(
t
))
0
.
097500000000000031
>>>
>>>
# 예
2
:
'
7
'
일 확률이 가장 높다고 추정함
(
0
.
6
)
>>>
y
=
[
0
.
1
,
0
.
05
,
0
.
1
,
0
.
0
,
0
.
05
,
0
.
1
,
0
.
0
,
0
.
6
,
0
.
0
,
0
.
0
]
>>> ...
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