
Numbers and Errors 47
0, 1,...,n} of n +1 values instead of X. This way we are approximating
the original problem by the problem of finding the smallest among the n +1
numbers in X
n
. Suppose that this smallest number in X
n
equals
ˆ
f =4/9,
and the exact minimum of X is f
∗
=1/12 (see Figure 2.2). Then |f
∗
−
ˆ
f| =
|1/12−4/9| =13/36 is the absolute truncation error of the considered method.
Definition 2.5 (Round-off Error) The error caused by the approxi-
mation of a numerical value with a value represented by fewer digits is
called the round-off error.
Example 2.13 Assume that we want to write our answer
˘
f to the problem in
the previous example as a five-digit de ...