
176 Numerical Methods and Optimization: An Introduction
(0, +∞) such that x = y and any α ∈ (0, 1), the following inequality holds:
1
αx +(1− α)y
<
α
x
+
1 − α
y
∀α ∈ (0, 1),x,y ∈ (0, +∞),x = y. (8.15)
Multiplying both sides by (αx +(1− α)y)xy, which is positive, we obtain an
equivalent inequality
xy < (αx +(1− α)y)(αy +(1− α)x).
Since (αx+(1−α)y)(αy+(1−α)x)−xy = α(1−α)(x−y)
2
> 0, inequality (8.15)
is correct, hence f is strictly convex by definition.
Given X ⊂ IR
n
, discontinuities for a convex function f : X → IR c a n o n l y
occur at the boundary of X, as implied by the following theorem.
Theorem 8.3 A convex function is continuous in the interior int (X