
376 Numerical Methods and Optimization: An Introduction
Consider the i
th
component of (14.15):
y
(k+1)
i
= y
(k)
i
− α
k
d
(k)
i
=1− α
k
d
(k)
i
. (14.16)
Observe that if d
(k)
i
≤ 0, then y
(k+1)
i
> 0 for any α
k
> 0. If, on the other
hand, d
(k)
i
> 0, then
y
(k+1)
i
> 0 ⇔ 1 − α
k
d
(k)
i
> 0 ⇔ α
k
< 1/d
(k)
i
.
It is easy to see that the above inequality is satisfied for α
k
given by
α
k
= α min
i:d
(k)
i
>0
A
1/d
(k)
i
B
,
where 0 <α<1 (typically α =0.9or0.99ischosen).Notethatifd
(k)
=0
and d
(k)
≤ 0, then the problem is unbounded (there is no minimizer). Finally,
having computed y
(k+1)
i
, we need to find the corresponding feasible point of
the original problem (14.13) by applying the inverse scaling operation, ...