Power Quality in Power Systems and Electrical Machines, 2nd Edition

Solution to Application Example 4.4

Following the notation of [7] one obtains the voltage equations:

$e_a=p{\mathrm{\Psi }}_a-r\cdot i_a$

  (E4.4-1a)

$e_b=p{\mathrm{\Psi }}_b-r\cdot i_b$

  (E4.4-1b)

$e_c=p{\mathrm{\Psi }}_c-r\cdot i_c$

  (E4.4-1c)

$e_{fd}=p{\mathrm{\Psi }}_{fd}+r_{fd}\cdot i_{fd}$

  (E4.4-1d)

$0=p{\mathrm{\Psi }}_{kd}-r_{kd}\cdot i_{kd}+v_{kd}$

  (E4.4-1e)

$0=p{\mathrm{\Psi }}_{kq}-r_{}$