effect of grouping and ambient temperature is 0.7 x 0.97 = 0.69.
The factor for thermal insulation
is
still worse than this combin-
ation, and therefore Q is the only one to be used.
Having chosen the
relevant
correction factors, we now apply them
to the nominal rating of the protection 7
n
as divisors in order to
calculate the current-carrying capacity I
z
of the cable.
Fuseboard
Grouping 0.7
Ambient temperature
0.97
Thermal insulation 0.5
O
Load
Current-carrying capacity
The required formul ...
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