December 2014
Intermediate to advanced
541 pages
17h 38m
English
Content preview from Green Chemical Engineering
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150 Green Chemical Engineering
Solving this equation sequentially for i = 1,2,3,…,N, we get
C
kC
k
C
kC
k
C
kC
k
A
A
A
A
A
A
1
10
1
2
21
2
3
32
3
14 1
2
14 1
2
14 1
2
=
+−
=
+−
=
+−
τ
τ
τ
τ
τ
τ
.
..
.
CC
kC
k
Af AN
NAN
N
==
+−
−
14 1
2
1
τ
τ
(3.33)
The nal conversion X
Af
= 1 − (C
Af
/C
A0
) is calculated from the value of C
Af
.
PROBLEM 3.5
A second-order reaction with rate constant k = 0.05 m
3
/kmol (min) is carried out in a series
of three unequal-volume CSTRs with space time τ
1
= 1 min, τ
2
= 2 min and τ
3
= 4 min, respec-
tively. The feed concentration of reactant A is C
A0
= 2 kmol/m
3
. What is the net conversion?
What is the conversion if the feed direction is reversed? (i.e. τ
1
= 4, ...
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