April 2018
Beginner to intermediate
500 pages
11h 26m
English
L1 regularization works in a similar way as that of L2; however, the cost function for L1 regularization is different than L2 regularization, as follows:

Let's implement the L1 regularization in code; now we see the corresponding outputs as follows:

Note that, as the regularization term does not involve squaring in L1 regularization, we ...
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