Emax ¼ (MTW
i
Wreq)={Max[(N 1) (BOH þ Wreq), transmission rate
(RTD þ OLT processing time þ ONU processing time)] (5:2)
þ MTW
i
þ BOH
If MTW
i
is set to a small value, the limited service IPACT will meet the require-
ments of minimizing the delay (Sect. 5.2.3 B). However, we still have to satisfy
requirements A and C of Sect. 5.2.3. Due to the fact that Ethernet packets cannot
be fragmented in EPON, a small MTW
i
setting has the following problems
regarding these requirements.
Requirement 5.2.3 A: The fairness diminishes when the packet sizes used
between the users are different. For instance, if MTW
i
is 4000 bytes, an unfair
allocation with a difference in bandwidth of up to 25% (¼(40003000) 100/
4000) will occur between a user who transmits 1500-byte ...