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Programming Perl, 4th Edition
book

Programming Perl, 4th Edition

by Tom Christiansen, brian d foy, Larry Wall, Jon Orwant
February 2012
Intermediate to advanced
1184 pages
37h 17m
English
O'Reilly Media, Inc.
Content preview from Programming Perl, 4th Edition

Other Tricks You Can Do with Hard References

As mentioned earlier, the backslash operator is usually used on a single referent to generate a single reference, but it doesn’t have to be. When used on a list of referents, it produces a list of corresponding references. The second line of the following example does the same thing as the first line, since the backslash is automatically distributed throughout the whole list:

@reflist = (\$s, \@a, \%h, \&f);     # List of four references
@reflist = \($s,  @a   %h,  &f);     # Same thing

If a parenthesized list contains exactly one array or hash, then all of its values are interpolated, and references to each are returned:

@reflist = \(@x);                    # Interpolate array, then get refs
@reflist = map { \$_ } @x;           # Same thing

This also occurs when there are internal parentheses:

@reflist = \(@x, (@y));              # But only single aggregates expand
@reflist = (\@x, map { \$_ } @y);    # Same thing

If you try this with a hash, the result will contain references to the values (as you’d expect), but also references to copies of the keys (as you might not expect).

Since array and hash slices are really just lists, you can backslash a slice of either of these to get a list of references. Each of the next three lines does exactly the same thing:

@envrefs = \@ENV{"HOME", "TERM"};         # Backslashing a slice
@envrefs = \( $ENV{HOME},  $ENV{TERM} );  # Backslashing a list
@envrefs = ( \$ENV{HOME}, \$ENV{TERM} );  # A list of two references

Since functions can return lists, you can apply a backslash ...

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Publisher Resources

ISBN: 9781449321451Errata Page