Orthogonal Comparison ◾ 113
Recall(BH)
BHr/t
(9.6)
Another way to think of recall(BH) is as the reduction of recall(B) by
the amount of recall(H):
Recall(BH)
Recall(B)* Recall(H)
= (Br/t)*(Hr/t)
= Br * Hr/(t * t)
(9.7)
Combining Equation9.6 with Equation9.7 yields:
(9.8)
which becomes
(9.9)
(9.10)
Combining Equations9.9 and 9.5 with Equation9.10 produces
Precision(BH)
Br * Hr * N/(t *B* H)
(9.11)
Note that in the special case where t = B*H/N (the expected value),
Precision = Br * Hr/t * t = Recall
As an example of the power of this approach to increase precision
without causing serious degradation in recall, suppose B and H queries
both have 90% recall, but only 10% precisio ...