October 2020
Intermediate to advanced
450 pages
15h 32m
English
Content preview from Electrotechnical Systems
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302 Electrotechnical Systems
the module of the current space vector i
s
(5.132) exceeds I
0
; the controller output
gives the demanded PMSM torque. The specied ux linkage value is dened as
follows [10].
Denote I
q
= L
d
i
sq
/Ψ
r
, I
d
= L
d
i
sd
/Ψ
r
, dl = (L
q
− L
d
)/L
d
, m = T
e
L
d
/1.5Z
p
Ψ
r
2
, f
s
= Ψ
s
/Ψ
r
,
then from (5.130), (5.131) it follows:
fIdl I
sd q
=+ ++()
()11
22
2
(5.134)
mI Idl
qd
= ()
1
−
(5.135)
The values of I
q
, I
d
are selected so that under a specied torque the motor current
(5.132) is minimum or is equivalent under the specied current the torque is maxi-
mum. If we substitute
II
I
qd
=
0
22
−
in (5.135), nd minimum for I
d
and exclude
II
I
qd
0
22
=+
in the resulting ...
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