
50 Nonlinear Optimal Control Theory
Then, |T | = |I| and for each i the mapping τ → L
τ
(g
i
) is differentiable at all
points of T .
We now show that for each g in C(I × Z) the mapping τ → L
τ
(g) is
differentiable at all points of T . Let τ
0
be a point in T and for τ 6= τ
0
define
∆
τ,τ
0
(g) =
L
τ
(g) − L
τ
0
(g)
τ − τ
0
.
Then to show that τ → L
τ
(g) is differentiable at τ
0
it suffices to show that
for τ
1
, τ
2
→ τ
0
that
∆
τ
1
,τ
0
(g) − ∆
τ
2
,τ
0
(g) → 0. (3.3.6)
For g
i
as in the preceding paragraph,
|∆
τ
1
,τ
0
(g) − ∆
τ
2
,τ
0
(g)| ≤ |∆
τ
1
,τ
0
(g − g
i
)| + |∆
τ
2
,τ
0
(g − g
i
)|
+ |∆
τ
1
,τ
0
(g
i
) − ∆
τ
2
,τ
0
(g
i
)|.
From the definition of ∆
τ,τ
0
(g) and (3.3.5) we get that each of the first two
terms on the right do not