
210 Nonlinear Optimal Control Theory
Since (λ
0
, λ, µ) is a unit vector, it is different from zero.
From Eq s. (7.2.7), (7.2.8), and (7.2.9) and the continuity of the partials of
f, g, and h, we ge t
λ
0
∂f
∂x
j
(0) +
r
X
i=1
λ
i
∂g
i
(0)
∂x
j
+
k
X
i=1
µ
i
∂h
i
(0)
∂x
j
= 0. (7.2.10)
From (7.2.6) and (7.2.9) we see that λ
i
≥ 0, i = 0, 1, . . . , r and that λ
i
= 0 for
i = r + 1, . . . , m. Thus, λ
0
≥ 0 and λ ≥ 0. Since g
i
(0) = 0 for i = 1, . . . , r and
λ
i
= 0 for i = r + 1 , . . . , m, we have that λ
i
g
i
(0) = 0 for i = 1 , . . . , m. Also,
we can take the upper limit in the se cond term in (7.2.10) to be m and write
λ
0
∂f
∂x
j
(0) +
m
X
i=1
λ
i
∂g
i
(0)
∂x
j
+
k
X
i=1
µ
i
∂h
i
(0)
∂x
j
= 0.
This completes the ...