
Existence Theorems; Compact Constraints 89
For each n, the admissible pair (ψ
n
, µ
n
) in the subsequence satisfies
ψ
n
(t) = ψ
n
(t
0n
) +
Z
t
t
0n
f(s, ψ
n
(s), µ
ns
)ds.
If we let n → ∞ and use (4.3.12), (4.3.13), and Lemma 4.3.3, we get that
ψ
∗
(t) = ψ
∗
(t
0
) +
Z
t
t
0
f(s, ψ
∗
(s), µ
∗
s
)ds (4.3.14)
for t ∈ I. A similar argument gives
lim
n→∞
Z
t
1n
t
0n
f
0
(s, ψ
n
(s), µ
n,s
)ds =
Z
t
1
t
0
f
0
(s, ψ
∗
(s), µ
∗
s
)ds. (4.3.15)
From (t
0
, x
0
, t
1
, x
1
) ∈ B, (4.3.13), (4.3.14), and the fact that µ
∗
t
is concentrated
on Ω(t) we get that (ψ
∗
, µ
∗
) is an admissible pair.
Since g is lower semicontinuous
lim inf
n→∞
g(e(ψ
n
)) ≥ g(e(ψ
∗
)).
From this and (4.3.11) a nd (4.3.15) we get that
m = lim
n→∞
J(ψ
n
, µ
n
) ≥ J(ψ
∗
, µ
∗