
264 Nonlinear Optimal Control Theory
Hence
t
1
= {−v
0
/d + [(v
0
/d)
2
+ 4(gy
1
/2d
2
)]
1/2
}/(gy
1
/d
2
).
We have just shown that the set of ordinary admissible pairs is not empty
and hence that the set o f relaxed admissible pairs is not empty. Since inf{t
f
: t
f
terminal time o f an admissible trajectory} is les s than or equal to t
1
, it follows
that we can restrict our a ttention to admissible pairs defined on compact
intervals [0, t
f
] ⊆ [0, t
1
]. If we set I = [0, t
1
], we need only consider
b
f on
I × R
2
.
It is easy to show tha t there exists a constant K such that
|h(ξ, η), f(τ, ξ, η)i| ≤ K(|ξ|
2
+ |η|
2
+ 1)
for all t in I, and all (ξ, η) in R
2
and all −π ≤ z ≤ π. Hence ...