Existence Theorems; Compact Constraints 99
will be convex. To se e this, let by = (y
0
1
, y
1
) and by
2
= (y
0
2
, y
2
) be two points in
Q
+
(t, x). Then there exist points z
1
and z
2
in Ω(t), such that
y
0
1
≥ f
0
(t, x, z
1
) y
1
= A(t)x + B(t)z
1
+ h(t) (4.5.3)
y
0
2
≥ f
0
(t, x, z
2
) y
2
= A(t)x + B(t)z
2
+ h(t). (4.5.4)
Let α and β be two real numbers such that α ≥ 0, β ≥ 0, and α + β = 1.
If we multiply the relations in (4.5.3) by α, the relations in (4.5.4) by β, and
add, we get
αy
0
1
+ βy
0
2
≥ αf
0
(t, x, z
1
) + βf
0
(t, x, z
2
)
αy
1
+ βy
2
= A(t)x + B(t)(αz
1
+ βz
2
) + h(t).
Since Ω(t) is convex, there exists a point z
3
in Ω (t) such that z
3
= αz
1
+ βz
2
.
From the convexity of f
0
in z, we g et
αf
0
(t, x, z
1
) + βf
0
(t, x, z
2
) ≥ f
0
(t, x, αz
1
+ βz
2
) = f
0
(t, x, z
3
).
Hence
αy
0
1
+ βy
0
2
≥ f
0
(t, x, z
3
)
αy
1
+ βy
2
=