May 2011
Beginner
492 pages
14h 16m
English
Content preview from Heat and Thermodynamics
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Solved Problems
Q 1. Volume of 1 gm of water at 0°C and at 760 mm pressure is 1cc and volume of 1 gm of ice at 0°C and at 760 mm pressure is 1.0908 cc. Calculate the change in melting point of ice by 1 atmosphere increase of pressure.
Given L = 80 calories at N.T.P.
Ans. From the given data, (vliq − vsol) = −0.0908
T = 273
dp = 1 atmosphere
= 76 × 13.6 × 981 dynes/sq. cm
Putting the values in Eq. 6.10, we get
or
2nd method
From the given data, (vliq − vsol) = −0.0908
T = 273
dp = 1 atmosphere ...
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