
Since
π
4
1
π
6
5
10π
24
5
5π
12
and
z
1
z
2
5
ffiffiffi
2
p
ðcosðπ=4Þ1 i sinðπ=4ÞÞ
2ðcosðπ=6Þ1 i sinðπ=6ÞÞ
5
ffiffiffi
2
p
2
cos
π
12
1 i sin
π
12
We can use z
2
5 z z 5 r rðcosðθ 1 θÞ1 i sinðθ 1 θÞÞ5 r
2
ðcos 2 θ 1 i sin 2θÞ
2.15 DeMoivre’s Theorem
z
n
5 r
n
ðcos n θ 1 i sin nθÞ
where n is a positive integer.
Let r 5 1 to getðcos θ1i sin θÞ
n
5 cos nθ 1 i sin nθ.
Example Compute ð11iÞ
6
ð11iÞ
6
5
ffiffiffi
2
p
cos
π
4
1i sin
π
4
6
5
ffiffiffi
2
p
6
cos 6
π
4
1 i sin 6
π
4
0
@
1
A
5 8 cos
3π
2
1 i sin
3π
2
0
@
1
A
528i
2.16 Euler’s Formula
e
ix
5 cos x 1 i sin x:
30 Mathematical Formulas for Industrial and Mechanical Engineering