C++ How to Program, 10/e

Answers to Self-Review Exercises

1. 20.1

   1. 16, because an $O\left(n^2\right)$ algorithm takes 16 times as long to sort four times as much information.

   2. O(n log n).

2. 20.2 Both of these algorithms incorporate “halving”—somehow reducing something by half. The binary search eliminates from consideration half of the array after each comparison. The merge sort splits the array in half each time it’s called.

3. 20.3 The insertion sort is easier to understand and to implement than the merge sort. The merge sort is far more efficient (O(n log n)) than the insertion sort ($O\left(n^2\right)$).

4. 20.4 In a sense, it does not really sort these two sub-arrays. It simply keeps splitting the original array in half until it provides a one-element sub-array, which is, of course, sorted. It then ...