November 2017
Intermediate to advanced
670 pages
17h 35m
English
Let's use a truth table to prove the (a → b)∧(b → a) ≡ a ↔ b equation:
|
a |
b |
a → b |
b → a |
(a → b)∧(b → a) |
a ↔ b |
|
T |
T |
T |
T |
T |
T |
|
T |
F |
F |
T |
F |
F |
|
F |
T |
T |
T |
F |
F |
|
F |
F |
T |
T |
T |
T |
In other words, a biconditional proposition (a ↔ b) is equivalent to the conjunction of a conditional proposition (a → b) and its converse (b → a).