or f (0), that is, the initial value of a function f (t) in any time domain is
equal to Lt
s
sFs
→∞
()
. That is, it can be expressed as follows:
LtLt
ts
ftsFs
→→
∞
=
0
()
()
Where
FsLft()[()]=
Example 7.28Verify the initial value theorem for the functione
4t
cos 2t.
Solution: Given f(t) =e
4t
cos 2t
Now, L[ f (t)] =L[e
4t
cos 2t]
=
−
−+
()
()
[
s
s
4
42
22
Using first shifting property]]
()
()
=
−
−+
=
s
s
Fs
4
44
2
Now, the L.H.S of the initial value theorem can be given as follows:
LtLt
tt
t
ft
et
e
→
=
=
00
4
0
2
0
1
()
=⋅
⋅
→
cos
cos
(7.1)
The R.H.S of the initial ...
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