Step 3: The Thevenin’s equivalent circuit is shown
in Figure 5.65.
I
V
Zj
jj
=
++
=
∠°
−+
+
=
∠°
Th
Th
54
15175011
37517145
4
15175011
87
..
..
..
.551314
15175011
15786562
9615631
−
=
∠°
∠−°
=∠°
j.
..
..
..
Current through the (5 +j4 Ω) impedance is
==∠I9615645..°A
.
Example 5.20 Find the current through (5 +j4) Ω
impedance in the network shown in Figure 5.66 using
Norton’s theorem.
Solution: Note that this problem has already been
solved using Thevenin’s theorem. Here, we will use
Norton’s theorem and verify the result.
Step 1:Short-circuit the branch ...
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