Example 6.9The constant voltage of 100 V is applied at t= 0 to a series R–C circuit
having
RC=Ω=5M,20Fµ
. By assuming no initial charge to the capacitor, fi nd current i and
the voltage across R and C.
Solution:
V
R
C
=
==×
==×
−
100
5510
202010
6
6
V
M
FF
ΩΩ
µ
Now, current can be expressed as follows:
i
V
R
ee
e
e
t
RC
t
t
t
==
×
=
=×
−
−
×××
−
−
−
−
100
510
20
10
2010
6
5102010
6
100
6
1
66
000
Α
Voltage across R
=Ri×
=×××
=
−
−
−
5102010
100
66
100
100
e
e
t
t
V
Voltage across capacitor =V – Voltage across resistor
=−
=−
−
−
100100
1001
100
100
e
e
t
t
V
Example 6.10A capacitor of 12 pF is to be charged and is designed such that the time
taken by the capacitor voltage to ...
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