
138 Network Analysis and Synthesis
Voltage drop across series branch, V
CB
= IZ
3
=−
15 57 59 65 12 85134
199 4831
..
..
∠°V
Voltage applied across terminals AB, V
AB
= V
AC
+ V
CB
= (267.33 − j1.8.8) V
= 288.62∠22.15° V
Example 3.27 In a series–parallel circuit
shown in Figure 3.54, parallel branches A, B
and C are in series with branch D. Calculate
(a) The impedance of the overall circuit;
(b) Current taken by the circuit and (c) Power
consumed by each and the total power
consumed.
Solution: The impedance of branch A is, Z
A
=
2 + j0 = 2 Ω
The impedance of branch B is,
Z
ZZ
ZZ
j
j
j
j
j
j
j
j
AB
AB
AB
=
+
=
+
++
=
+
+
=
+
+
×
−
−
=
−
23 4
23 4
68
54
68
54
54
54
62
()
jj
j
16
54
1510