
56 Network Analysis and Synthesis
=−=
23 1220 0
84 4
()
∆=−
22
250
201
051
()for I
=− +=
10 10 0
Therefore, I
2
2
0
0=
.
Hence, current through branch BC = I
2
= 0 A
2.6 METHODS OF SOLVING COMPLEX NETWORK PROBLEMS
In this section, we have taken up large number of complex network problems having either DC
or AC excitations (voltage or current).
2.6.1 Numerical Problems Based on Kirchhoff’s Laws
Example 2.21 Calculate the voltage V
s
across the open switch
in the circuit of Figure 2.43.
Solution: By applying KVL, starting from point A in the
clockwise direction and considering the polarity of sources, we
get the follo ...