Network Functions − s-Domain Analysis of Circuits 423
Dividing equation (10.2) by equation (10.1), we get the equation as follows:
Vs
Vs
Cs
Is
R
Cs
Is
Cs
R
Cs
Cs
RCs
C
o
i
()
()
()
()
=
+
=
+
=
+
1
1
1
1
1
1
ss
RCs
=
+
1
1
Vs
VsRCs
o
i
()
()
=
+
1
1
is the
required transfer function.
Example 10.8 Determine the transfer function of the network
shown in Figure 10.22.
Solution: The s-domain equivalent network of the given
network is shown in Figure 10.23.
Applying KVL to the given network, we get the following:
V
i
(s) =RI (s) +sLI (s)
= (R+sL) I (s) (10.3)
Moreover,
V
o
(s) =sLI (s) (10.4)
Dividing equation (10.4) by equation (10.3), the equation can be
written as follows: ...
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