Solution: Firstly, let us check whether the given impedance function is of R–C or of R–L type.
Z
()
()()()
()()()
0
135
0246
==
∞
Z(∞) = 0
In this case, Z(0) >Z(∞)
Therefore, the given impedance is of R–C type.
Foster form-I can be obtained as in the following:
Zs
sss
ssss
P
s
P
s
P
s
P
s
()
()()()
()()()
=
+++
+++
=+
+
+
+
+
135
246
24
0
24
6
++
↓↓↓
6
s
2246
ss
(12.32)
Now,
Ps
sss
ssss
s
0
0
135
246
135
246
=⋅
+++
+++
=
=
()()()
()()()
()()()
()()(
))
=
5
16
Ps
sss
ssss
sss
s
2
2
2
135
246
13
=+⋅
+++
+++
=
++
=−
()
()()()
()()()
()()(
++
++
=
−
−
=
=
5
46
113
224
3
16
2
)
()()
()()()
()()
sss
s
Ps
ss
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