September 2008
Beginner
834 pages
37h 13m
English
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5.4 COMPENSATION THEOREM
The circuit in Fig. 5.4-1(a) has a resistor marked as R. It has a nominal value of 2 Ω. Mesh analysis was carried out to find the current in this resistor and the current was found to be 1 A as marked in the circuit as in Fig. 5.4-1(a).
Now, let us assume that the resistor value changes by ΔR to R+ΔR. Correspondingly all circuit variables change by small quantities as shown in Fig. 5.4-1(b). The current through that resistor will also change to i+ Δi. We can conduct a mesh analysis once again and get a new solution. However, we can do better than that. We can work out changes in variables everywhere by solving a single-source circuit and then construct the circuit solution by adding change to the initial solution value. ...
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