8.6 LINEAR EQUIVALENCE
The output of an LFSR s0(0), s0(1), … may be generated by more than one characteristic polynomial and initial state.
Example 8.6
The LFSRs with characteristic polynomials and initial states
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both generate the sequence s = (1, 1, 0, 1, 1, 0,…). Note that an LFSR to generate a given n-sequence of 0's and 1's σ = (σ(0), σ(1), …, σ(n−1)) always exists as σ could be used as the initial state of the n-stage LFSR with any coefficient vector
More relevant are the questions
| Q1. | What is the minimum number of stages needed by an LFSR to generate σ? |
| Q2. | What is the minimal polynomial of σ, the characteristic polynomial of the minimal-length LFSR that generates σ? |
The linear equivalence L(σ) of the n-sequence σ = (σ(0), σ(1), …, σ(n−1)) is the length of the shortest LFSR that generates σ.
The principal properties of linear equivalence are summarized in the next proposition.
Proposition 8.7: [Beker and Piper, 1982, p. 200; Menezes et al., 1996, p. 198]1 the n-sequence σ = (σ(0), σ(1), …, σ(n−1))
| 8.7a | If σ is of length n; then1 ![]() |
| (Note, in analogy with the convention for a summation or product with an empty index set, a 0-stage LFSR always outputs 0.) | |
| 8.7b | The linear equivalence of σ and v, possibly of different lengths, satisfies L(σ + v) ≤ L( ... |
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