Digital Circuits & Design, 1st Education by Pearson

Logic Circuit Design: Arithmetic Operation | 5.59

(b) Take 10’s complement of (N) = 8 and add it to (M)=4

10’s complement of 8 in XS-3 code = 0101 (2’s complement of 1011)

0 0 0

(M) =

4 0111

10’s complement of (N) =

2 0101

(M) + (10’s complement of (N)) =

0 6 0 1100

1100

+ 1101

Carry is 0 so compute 10’s complement (−) 4 1 1001

End carry is zero, so compute 10’s complement and place negative sign

10’s complement of 1001 in XS-3 code = (−) 0111 (2’s complement of 1001) Ans.

5.14 | COMPARATOR

Comparator is a device that compares two binary bits. Output of device gives logic 1 if

one bit is equal or less than or greater than other bit. Let x binary ...