•In rst three possible cases there is no need of borrow from next bit.
•In case-IV, there is need of borrow from next bit.
•Borrow is taken from the next higher place valued digit as (10)
3
or (3)
10
(base value 3).
•Taken borrow is added to minuend and sum is obtained (10)
3
+ (0)
3
= (10)
3
or (3)
10
+
(0)
10
= (3)
10
•Finally, subtrahend is subtracted from partial sum to get the difference,
•i.e. (10)
3
– (1)
3
= (2)
3
or (3)
10
– (1)
10
= (2)
10
•Borrow taken by previous digit column is subtracted from minuend of present digit
column.
•When minuend is larger than or equal to subtrahend then there will be no borrow.
•
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