ExamplE15.5 Design an astable multivibrator using 555 timer for a free-running
frequency of 1.07 kHz and a duty cycle of 75%.
SolutionDesign and nd the values of R
A
and R
B
.
Free-running frequency, f
T
=
1
Total time, T
f
===
×
=
11
107
1
10710
0 93458
3
.
.
.
kHz
ms
Duty cycle
ON
=×
T
T
100
T
T
ON
Duty cyclems
ms=
×
=
×
=
100
750 93458
100
0 700935
.
.
TT
HighON
ms
==
0 700935.
TTT
LowON
msmsms
=−=−=
0 934580 7009350 23365...
Let C
=
01.
μ
F
TR
C
LowB
=
0 693.
R
T
C
B
Low
ms
F
k==
×
=
0 693
0 23365
0 69301
3 37157
.
.
..
.
μ
ΩAns.
TRRC
High
AB
=+
(
)
0 693.
R
T
C
R
A
High
B
ms
F
kk
=−=
×
−=
0 693
0 700935
0 69301
3 371576 74293
.
.
..
..
μ
ΩΩ
ΩAns.
ExamplE 15.6 In ...
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