Solving for the particular integral of a differential equation for sinusoidal input has been ren-
dered easy by the use of complex exponential function as shown in the previous sections.
However, deriving the differential equation remains a tedious affair even now. Arriving at
the proper elimination steps requires considerable ingenuity in the case of circuits containing
many inductors and capacitors, but we can avoid all that. We proceed to see how.
The steady-state response of the second mesh current i
2
in the circuit in Fig. 8.3-1 for
a complex exponential input of V
m
e
j
ω
t
was noted as ...
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