10.10 GENERAL ANALYSIS PROCEDURE FOR SINGLE TIME CONSTANT RL CIRCUITS
(b)
(a)
10 Ω
10 Ω
7.07 V
v
0
+
+
–
–
0 A
10 Ω
10 Ω
v
0
+
+
–
–
j2.5 Ω
10
45°
2
Fig. 10.10-9 Circuits
for Zero-State
Response due to first
Voltage Source in
Example 10.10-3
(b)
(a)
10 Ω
10 Ω
v
0
+
+
––
j5 Ω
10
–30°
2
10 Ω
10 Ω
–5 V
v
0
+
–
0 A
Fig. 10.10-10 Circuits
for Zero-State
Response due to
Second Voltage
Source in Example
10.10-3
10 Ω
10 Ω
10 Ω
10 Ω
2
–60°
2
(a)
(b)
i
s
(t)
1 A
v
0
v
0
+
+
–
–
0 A
j2.5 Ω
Fig. 10.10-11 Circuits
for Zero-State
Response due to
Current Source in
Example 10.10-3
Therefore, it is a current source of zero value, i.e., it is an open-circuit. Therefore, v
O
at
t 0
+
is 7.07/2 3.535 V.
The angular frequency of v
S1
(t) is 10 ...
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