8.6SINUSOIDAL STEADY-STATE RESPONSE FROM PHASOR EQUIVALENT CIRCUIT
(V)
v
S
(t)
i
1
(t)
t
300
200
100
–100
1
0.5
–0.5
–1
–1.5
(A)
t in ms
t + 10
t + 20t + 30
t + 40
(a)
–200
–300
(V)
v
C
(t)
i
1
(t)
t
300
200
100
–100
1
0.5
–0.5
–1
–1.5
(A)
t in ms
t + 10
t + 20
t + 30
t + 40
(b)
–200
–300
Fig. 8.6-4 (a) Applied Voltage and Current and (b) Capacitor Voltage and
Current in Example 8.6-2
v
S
v
O
v
S
= 300 cos 100t V
i
x
i
y
+
–
+
–
+
–
+
–
1 Ω
25 Ω
0.25 Ω
1 H
0.25 H
0.5
di
y
dt
0.5
di
x
dt
Fig. 8.6-5 Circuit for Example 8.6-3
Find the (i) source current (ii) source power (iii) output voltage and (iv) power delivered
to 25 Ω resistor in the circuit in Fig. 8.6-5.
Solution
The source voltage phasor is 300∠0° V.
The dependent sources ...
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