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2.7 SUMMARY
SOLUTION
The current that flows through 100 kΩ at the output side is 100i
x
from the bottom terminal
to the top terminal. Therefore, v
o
10
7
i
x
V. Therefore, the voltage generated by
the VCVS at the input side is 0.002 10
7
i
x
2 10
4
i
x
V with polarity as shown in
Fig. 2.6-5.
Therefore, voltage across 40 kΩ resistance is 20 10
3
i
x
2 10
4
i
x
= 0 V.
Therefore, current through 40 kΩ resistance is 0 A.
Applying KVL in the first mesh, we get, voltage drop across 10 kΩ v
s
V.
Therefore, current through 10 kΩ resistance 10
4
v
s
A.
Current through 40 kΩ is zero. Therefore, by KCL, i
x
10
4
v
s
A.
We know that v
o
10
7
i
x
V.
v
o
10
7
i
x
10
7
10