enter with same sign in the incidence matrix. Therefore, the product of the i
th
row of A
a
and
the j
th
column of B
a
T
will be equal to zero in that case.
Now, assume that the i
th
node is not present in the j
th
loop. Then, no branch that is
incident at the i
th
node can be present in the j
th
loop. Then, the i
th
row of A
a
and the j
th
column of B
a
T
will not contain non-zero entries in similarly placed locations. Therefore,
the product of the i
th
row of A
a
and the j
th
column of B
a
T
will be zero.
Thus, the product of the i
th
row of A
a
and the j
th
column of B
a
T
will always be equal
to zero for any i and j. We get an important result from this reasoning.
A
a
B
a
T
0(17.5-1)
This is ...
Become an O’Reilly member and get unlimited access to this title plus top books and audiobooks from O’Reilly and nearly 200 top publishers, thousands of courses curated by job role, 150+ live events each month, and much more.
O’Reilly covers everything we've got, with content to help us build a world-class technology community, upgrade the capabilities and competencies of our teams, and improve overall team performance as well as their engagement.
Julian F.
Head of Cybersecurity
I wanted to learn C and C++, but it didn't click for me until I picked up an O'Reilly book. When I went on the O’Reilly platform, I was astonished to find all the books there, plus live events and sandboxes so you could play around with the technology.
Addison B.
Field Engineer
I’ve been on the O’Reilly platform for more than eight years. I use a couple of learning platforms, but I'm on O'Reilly more than anybody else. When you're there, you start learning. I'm never disappointed.
Amir M.
Data Platform Tech Lead
I'm always learning. So when I got on to O'Reilly, I was like a kid in a candy store. There are playlists. There are answers. There's on-demand training. It's worth its weight in gold, in terms of what it allows me to do.