enter with same sign in the incidence matrix. Therefore, the product of the i
th
row of A
a
and
the j
th
column of B
a
T
will be equal to zero in that case.
Now, assume that the i
th
node is not present in the j
th
loop. Then, no branch that is
incident at the i
th
node can be present in the j
th
loop. Then, the i
th
row of A
a
and the j
th
column of B
a
T
will not contain non-zero entries in similarly placed locations. Therefore,
the product of the i
th
row of A
a
and the j
th
column of B
a
T
will be zero.
Thus, the product of the i
th
row of A
a
and the j
th
column of B
a
T
will always be equal
to zero for any i and j. We get an important result from this reasoning.
A
a
B
a
T
0(17.5-1)
This is ...
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