Electric Circuits and Networks, Ist Edition by Pearson

Substituting for V

2

in terms of V

1

and solving for V

1

, we get,

This expression evaluated with T/

τ

 1 gives V

1

 V

2

 0.245 V for a 1 V amplitude

square wave input.

The key to the above derivation was our knowledge of step response of series RC

circuit. The input could be thought of as a sequence of unit steps and hence the output could

be strung together employing step response and zero-input response segments. Square waves

and more generalised versions of it (the so-called rectangular pulse waveforms that are

‘squarish’ waveforms with unequal half-cycle duration and unequal positive and negative

amplitudes) appear very frequently in Pulse Electronics ...