example in this section. Thus, the last rectangular pulse just prior to t 0 would have taken
place 1000 s back. The circuit in the example has a time constant of 1 s. Whatever be the
response value at the end of that pulse, we can expect it to have gone down to zero during
the intervening 999 s before the pulse located at t 0 comes up; –e
–999
is indeed a very
small number. Therefore, the term –i
fr
(0
+
) e
–t
in the solution for 0
+
≤t≤0.5T
–
can be dropped
because i
fr
(0
+
) will be close to zero. All the more so when T → ∞. Moreover, as T→ ∞, the
second solution term in Eqn. 13.1-3 is not needed since the first solution term itself takes
care of the entire ...
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